-7(y+1)+4(3y-4)=4(y-6)+13

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Solution for -7(y+1)+4(3y-4)=4(y-6)+13 equation:


-7(y+1)+4(3y-4)=4(y-6)+13

We simplify the equation to the form, which is simple to understand 
-7(y+1)+4(3y-4)=4(y-6)+13

Reorder the terms in parentheses
+(-7y-7)+4*(3y-4)=4*(y-6)+13

Remove unnecessary parentheses
-7y-7+4+*(+3y-4+)=+4+*(+y-6+)+13

Reorder the terms in parentheses
-7y-7+(+12y-16)=4*(y-6)+13

Remove unnecessary parentheses
-7y-7+12y-16=+4+*(+y-6+)+13

Reorder the terms in parentheses
-7y-7+12y-16=+(+4y-24)+13

Remove unnecessary parentheses
-7y-7+12y-16=+4y-24+13

We move all terms containing y to the left and all other terms to the right. 
-7y+12y-4y=-24+13+7+16

We simplify left and right side of the equation. 
+1y=+12

We divide both sides of the equation by 1 to get y. 
y=12

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