-7(y+2)+4(3y-4)=4(y-6)+12

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Solution for -7(y+2)+4(3y-4)=4(y-6)+12 equation: 



-7(y+2)+4(3y-4)=4(y-6)+12

We move all terms to the left:

-7(y+2)+4(3y-4)-(4(y-6)+12)=0

We multiply parentheses

-7y+12y-(4(y-6)+12)-14-16=0



We calculate terms in parentheses: -(4(y-6)+12), so:

4(y-6)+12

We multiply parentheses

4y-24+12

We add all the numbers together, and all the variables

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

5y-(4y-12)-30=0

We get rid of parentheses

5y-4y+12-30=0

We add all the numbers together, and all the variables

y-18=0

We move all terms containing y to the left, all other terms to the right

y=18

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