-7(y+3)+3(4y-3)=4(y-4)+12

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Solution for -7(y+3)+3(4y-3)=4(y-4)+12 equation:


-7(y+3)+3(4y-3)=4(y-4)+12

We simplify the equation to the form, which is simple to understand 
-7(y+3)+3(4y-3)=4(y-4)+12

Reorder the terms in parentheses
+(-7y-21)+3*(4y-3)=4*(y-4)+12

Remove unnecessary parentheses
-7y-21+3+*(+4y-3+)=+4+*(+y-4+)+12

Reorder the terms in parentheses
-7y-21+(+12y-9)=4*(y-4)+12

Remove unnecessary parentheses
-7y-21+12y-9=+4+*(+y-4+)+12

Reorder the terms in parentheses
-7y-21+12y-9=+(+4y-16)+12

Remove unnecessary parentheses
-7y-21+12y-9=+4y-16+12

We move all terms containing y to the left and all other terms to the right. 
-7y+12y-4y=-16+12+21+9

We simplify left and right side of the equation. 
+1y=+26

We divide both sides of the equation by 1 to get y. 
y=26

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