-7(y+3)=3y+29

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Solution for -7(y+3)=3y+29 equation: 



-7(y+3)=3y+29

We move all terms to the left:

-7(y+3)-(3y+29)=0

We multiply parentheses

-7y-(3y+29)-21=0

We get rid of parentheses

-7y-3y-29-21=0

We add all the numbers together, and all the variables

-10y-50=0

We move all terms containing y to the left, all other terms to the right

-10y=50

y=50/-10

y=-5

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