-7(y-5)=3y+47

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Solution for -7(y-5)=3y+47 equation: 



-7(y-5)=3y+47

We move all terms to the left:

-7(y-5)-(3y+47)=0

We multiply parentheses

-7y-(3y+47)+35=0

We get rid of parentheses

-7y-3y-47+35=0

We add all the numbers together, and all the variables

-10y-12=0

We move all terms containing y to the left, all other terms to the right

-10y=12

y=12/-10

y=-1+1/5

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