-7+3/14t=1/7t-8

Solution for -7+3/14t=1/7t-8 equation:

-7+3/14t=1/7t-8

We move all terms to the left:

-7+3/14t-(1/7t-8)=0


Domain of the equation: 14t!=0

t!=0/14

t!=0

t∈R



Domain of the equation: 7t-8)!=0

t∈R


We get rid of parentheses

3/14t-1/7t+8-7=0

We calculate fractions


21t/98t^2+(-14t)/98t^2+8-7=0

We add all the numbers together, and all the variables

21t/98t^2+(-14t)/98t^2+1=0

We multiply all the terms by the denominator


21t+(-14t)+1*98t^2=0

Wy multiply elements

98t^2+21t+(-14t)=0

We get rid of parentheses

98t^2+21t-14t=0

We add all the numbers together, and all the variables

98t^2+7t=0

a = 98; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·98·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*98}=\frac{-14}{196}
=-1/14
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*98}=\frac{0}{196}
=0
$