-7/10f+2/5=1/4f

Solution for -7/10f+2/5=1/4f equation:

-7/10f+2/5=1/4f

We move all terms to the left:

-7/10f+2/5-(1/4f)=0


Domain of the equation: 10f!=0

f!=0/10

f!=0

f∈R



Domain of the equation: 4f)!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

-7/10f-(+1/4f)+2/5=0

We get rid of parentheses

-7/10f-1/4f+2/5=0

We calculate fractions


320f^2/1000f^2+(-700f)/1000f^2+(-250f)/1000f^2=0

We multiply all the terms by the denominator


320f^2+(-700f)+(-250f)=0

We get rid of parentheses

320f^2-700f-250f=0

We add all the numbers together, and all the variables

320f^2-950f=0

a = 320; b = -950; c = 0;
Δ = b2-4ac
Δ = -9502-4·320·0
Δ = 902500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{902500}=950$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-950)-950}{2*320}=\frac{0}{640}
=0
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-950)+950}{2*320}=\frac{1900}{640}
=2+31/32
$