-7/10h+10=-1/5h+6

Solution for -7/10h+10=-1/5h+6 equation:

-7/10h+10=-1/5h+6

We move all terms to the left:

-7/10h+10-(-1/5h+6)=0


Domain of the equation: 10h!=0

h!=0/10

h!=0

h∈R



Domain of the equation: 5h+6)!=0

h∈R


We get rid of parentheses

-7/10h+1/5h-6+10=0

We calculate fractions


(-35h)/50h^2+10h/50h^2-6+10=0

We add all the numbers together, and all the variables

(-35h)/50h^2+10h/50h^2+4=0

We multiply all the terms by the denominator


(-35h)+10h+4*50h^2=0

We add all the numbers together, and all the variables

10h+(-35h)+4*50h^2=0

Wy multiply elements

200h^2+10h+(-35h)=0

We get rid of parentheses

200h^2+10h-35h=0

We add all the numbers together, and all the variables

200h^2-25h=0

a = 200; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·200·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*200}=\frac{0}{400}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*200}=\frac{50}{400}
=1/8
$