-7/2u+5/4=-3/8u=1/4

Solution for -7/2u+5/4=-3/8u=1/4 equation:

-7/2u+5/4=-3/8u=1/4

We move all terms to the left:

-7/2u+5/4-(-3/8u)=0


Domain of the equation: 2u!=0

u!=0/2

u!=0

u∈R



Domain of the equation: 8u)!=0

u!=0/1

u!=0

u∈R


We get rid of parentheses

-7/2u+3/8u+5/4=0

We calculate fractions


640u^2/256u^2+(-896u)/256u^2+96u/256u^2=0

We multiply all the terms by the denominator


640u^2+(-896u)+96u=0

We add all the numbers together, and all the variables

640u^2+96u+(-896u)=0

We get rid of parentheses

640u^2+96u-896u=0

We add all the numbers together, and all the variables

640u^2-800u=0

a = 640; b = -800; c = 0;
Δ = b2-4ac
Δ = -8002-4·640·0
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{640000}=800$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-800)-800}{2*640}=\frac{0}{1280}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-800)+800}{2*640}=\frac{1600}{1280}
=1+1/4
$