-7/2v-7/2=3/5v-2

Solution for -7/2v-7/2=3/5v-2 equation:

-7/2v-7/2=3/5v-2

We move all terms to the left:

-7/2v-7/2-(3/5v-2)=0


Domain of the equation: 2v!=0

v!=0/2

v!=0

v∈R



Domain of the equation: 5v-2)!=0

v∈R


We get rid of parentheses

-7/2v-3/5v+2-7/2=0

We calculate fractions


(-35v)/40v^2+(-24v)/40v^2+(-35v)/40v^2+2=0

We multiply all the terms by the denominator


(-35v)+(-24v)+(-35v)+2*40v^2=0

Wy multiply elements

80v^2+(-35v)+(-24v)+(-35v)=0

We get rid of parentheses

80v^2-35v-24v-35v=0

We add all the numbers together, and all the variables

80v^2-94v=0

a = 80; b = -94; c = 0;
Δ = b2-4ac
Δ = -942-4·80·0
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-94}{2*80}=\frac{0}{160}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+94}{2*80}=\frac{188}{160}
=1+7/40
$