-7/4v-5/2=5/3v-5

Solution for -7/4v-5/2=5/3v-5 equation:

-7/4v-5/2=5/3v-5

We move all terms to the left:

-7/4v-5/2-(5/3v-5)=0


Domain of the equation: 4v!=0

v!=0/4

v!=0

v∈R



Domain of the equation: 3v-5)!=0

v∈R


We get rid of parentheses

-7/4v-5/3v+5-5/2=0

We calculate fractions


(-180v^2)/48v^2+(-84v)/48v^2+(-80v)/48v^2+5=0

We multiply all the terms by the denominator


(-180v^2)+(-84v)+(-80v)+5*48v^2=0

Wy multiply elements

(-180v^2)+240v^2+(-84v)+(-80v)=0

We get rid of parentheses

-180v^2+240v^2-84v-80v=0

We add all the numbers together, and all the variables

60v^2-164v=0

a = 60; b = -164; c = 0;
Δ = b2-4ac
Δ = -1642-4·60·0
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-164)-164}{2*60}=\frac{0}{120}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-164)+164}{2*60}=\frac{328}{120}
=2+11/15
$