-7/5x=-9/7x+8

Solution for -7/5x=-9/7x+8 equation:

-7/5x=-9/7x+8

We move all terms to the left:

-7/5x-(-9/7x+8)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 7x+8)!=0

x∈R


We get rid of parentheses

-7/5x+9/7x-8=0

We calculate fractions


(-49x)/35x^2+45x/35x^2-8=0

We multiply all the terms by the denominator


(-49x)+45x-8*35x^2=0

We add all the numbers together, and all the variables

45x+(-49x)-8*35x^2=0

Wy multiply elements

-280x^2+45x+(-49x)=0

We get rid of parentheses

-280x^2+45x-49x=0

We add all the numbers together, and all the variables

-280x^2-4x=0

a = -280; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-280)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-280}=\frac{0}{-560}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-280}=\frac{8}{-560}
=-1/70
$