-7/8x+2=1-3/4x

Solution for -7/8x+2=1-3/4x equation:

-7/8x+2=1-3/4x

We move all terms to the left:

-7/8x+2-(1-3/4x)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-7/8x-(-3/4x+1)+2=0

We get rid of parentheses

-7/8x+3/4x-1+2=0

We calculate fractions


(-28x)/32x^2+24x/32x^2-1+2=0

We add all the numbers together, and all the variables

(-28x)/32x^2+24x/32x^2+1=0

We multiply all the terms by the denominator


(-28x)+24x+1*32x^2=0

We add all the numbers together, and all the variables

24x+(-28x)+1*32x^2=0

Wy multiply elements

32x^2+24x+(-28x)=0

We get rid of parentheses

32x^2+24x-28x=0

We add all the numbers together, and all the variables

32x^2-4x=0

a = 32; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·32·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*32}=\frac{0}{64}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*32}=\frac{8}{64}
=1/8
$