-70=3(t-5)-t

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Solution for -70=3(t-5)-t equation: 



-70=3(t-5)-t

We move all terms to the left:

-70-(3(t-5)-t)=0



We calculate terms in parentheses: -(3(t-5)-t), so:

3(t-5)-t

We add all the numbers together, and all the variables

-1t+3(t-5)

We multiply parentheses

-1t+3t-15

We add all the numbers together, and all the variables

2t-15

Back to the equation:

-(2t-15)



We get rid of parentheses

-2t+15-70=0

We add all the numbers together, and all the variables

-2t-55=0

We move all terms containing t to the left, all other terms to the right

-2t=55

t=55/-2

t=-27+1/2

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