-72+7y+7=3(4y-5)-5

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Solution for -72+7y+7=3(4y-5)-5 equation: 



-72+7y+7=3(4y-5)-5

We move all terms to the left:

-72+7y+7-(3(4y-5)-5)=0

We add all the numbers together, and all the variables

7y-(3(4y-5)-5)-65=0



We calculate terms in parentheses: -(3(4y-5)-5), so:

3(4y-5)-5

We multiply parentheses

12y-15-5

We add all the numbers together, and all the variables

12y-20

Back to the equation:

-(12y-20)



We get rid of parentheses

7y-12y+20-65=0

We add all the numbers together, and all the variables

-5y-45=0

We move all terms containing y to the left, all other terms to the right

-5y=45

y=45/-5

y=-9

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