-74+3y+2=3(3y-5)-3

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Solution for -74+3y+2=3(3y-5)-3 equation: 



-74+3y+2=3(3y-5)-3

We move all terms to the left:

-74+3y+2-(3(3y-5)-3)=0

We add all the numbers together, and all the variables

3y-(3(3y-5)-3)-72=0



We calculate terms in parentheses: -(3(3y-5)-3), so:

3(3y-5)-3

We multiply parentheses

9y-15-3

We add all the numbers together, and all the variables

9y-18

Back to the equation:

-(9y-18)



We get rid of parentheses

3y-9y+18-72=0

We add all the numbers together, and all the variables

-6y-54=0

We move all terms containing y to the left, all other terms to the right

-6y=54

y=54/-6

y=-9

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