-79=7q+3(4q-1)

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Solution for -79=7q+3(4q-1) equation: 



-79=7q+3(4q-1)

We move all terms to the left:

-79-(7q+3(4q-1))=0



We calculate terms in parentheses: -(7q+3(4q-1)), so:

7q+3(4q-1)

We multiply parentheses

7q+12q-3

We add all the numbers together, and all the variables

19q-3

Back to the equation:

-(19q-3)



We get rid of parentheses

-19q+3-79=0

We add all the numbers together, and all the variables

-19q-76=0

We move all terms containing q to the left, all other terms to the right

-19q=76

q=76/-19

q=-4

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