-7=1/3(3k+4)

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Solution for -7=1/3(3k+4) equation: 



-7=1/3(3k+4)

We move all terms to the left:

-7-(1/3(3k+4))=0



Domain of the equation: 3(3k+4))!=0

k∈R



We multiply all the terms by the denominator


-(1-7*3(3k+4))=0



We calculate terms in parentheses: -(1-7*3(3k+4)), so:

1-7*3(3k+4)

determiningTheFunctionDomain
-7*3(3k+4)+1

Wy multiply elements

-21k(3+1

Back to the equation:

-(-21k(3+1)



We add all the numbers together, and all the variables

-(-21k4=0

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