-7=1/3(x-12)

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Solution for -7=1/3(x-12) equation:



-7=1/3(x-12)
We move all terms to the left:
-7-(1/3(x-12))=0
Domain of the equation: 3(x-12))!=0
x∈R
We multiply all the terms by the denominator
-(1-7*3(x-12))=0
We calculate terms in parentheses: -(1-7*3(x-12)), so:
1-7*3(x-12)
determiningTheFunctionDomain -7*3(x-12)+1
Wy multiply elements
-21x(x+1
Back to the equation:
-(-21x(x+1)
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-21x(x+1
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-21x(x+1
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-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
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We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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-21x(x+1
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We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
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We calculate terms in parentheses: -(-21x(x+1), so:
-21x(x+1
We calculate terms in parentheses: -(-21x(x+1), so:
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We calculate terms in parentheses: -(-21x(x+1), so:
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We calculate terms in parentheses: -(-21x(x+1), so:
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We calculate terms in parentheses: -(-21x(x+1), so:
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