-7=2(z/3+5)=

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Solution for -7=2(z/3+5)= equation: 



-7=2(z/3+5)=

We move all terms to the left:

-7-(2(z/3+5))=0

We multiply all the terms by the denominator


-(2(z-7*3+5))=0



We calculate terms in parentheses: -(2(z-7*3+5)), so:

2(z-7*3+5)

We add all the numbers together, and all the variables

2(z-16)

We multiply parentheses

2z-32

Back to the equation:

-(2z-32)



We get rid of parentheses

-2z+32=0

We move all terms containing z to the left, all other terms to the right

-2z=-32

z=-32/-2

z=+16

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