-7k(k+5)=0

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Solution for -7k(k+5)=0 equation:



-7k(k+5)=0
We multiply parentheses
-7k^2-35k=0
a = -7; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·(-7)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*-7}=\frac{0}{-14} =0 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*-7}=\frac{70}{-14} =-5 $

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