-7n+4(3n+3)=6(n-5)-4n

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Solution for -7n+4(3n+3)=6(n-5)-4n equation: 



-7n+4(3n+3)=6(n-5)-4n

We move all terms to the left:

-7n+4(3n+3)-(6(n-5)-4n)=0

We multiply parentheses

-7n+12n-(6(n-5)-4n)+12=0



We calculate terms in parentheses: -(6(n-5)-4n), so:

6(n-5)-4n

We add all the numbers together, and all the variables

-4n+6(n-5)

We multiply parentheses

-4n+6n-30

We add all the numbers together, and all the variables

2n-30

Back to the equation:

-(2n-30)



We add all the numbers together, and all the variables

5n-(2n-30)+12=0

We get rid of parentheses

5n-2n+30+12=0

We add all the numbers together, and all the variables

3n+42=0

We move all terms containing n to the left, all other terms to the right

3n=-42

n=-42/3

n=-14

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