-7p-4(4-3p)=2(p-4)-23

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Solution for -7p-4(4-3p)=2(p-4)-23 equation: 



-7p-4(4-3p)=2(p-4)-23

We move all terms to the left:

-7p-4(4-3p)-(2(p-4)-23)=0

We add all the numbers together, and all the variables

-7p-4(-3p+4)-(2(p-4)-23)=0

We multiply parentheses

-7p+12p-(2(p-4)-23)-16=0



We calculate terms in parentheses: -(2(p-4)-23), so:

2(p-4)-23

We multiply parentheses

2p-8-23

We add all the numbers together, and all the variables

2p-31

Back to the equation:

-(2p-31)



We add all the numbers together, and all the variables

5p-(2p-31)-16=0

We get rid of parentheses

5p-2p+31-16=0

We add all the numbers together, and all the variables

3p+15=0

We move all terms containing p to the left, all other terms to the right

3p=-15

p=-15/3

p=-5

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