-7p-6(2-2p)=3(p-2)-18

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Solution for -7p-6(2-2p)=3(p-2)-18 equation: 



-7p-6(2-2p)=3(p-2)-18

We move all terms to the left:

-7p-6(2-2p)-(3(p-2)-18)=0

We add all the numbers together, and all the variables

-7p-6(-2p+2)-(3(p-2)-18)=0

We multiply parentheses

-7p+12p-(3(p-2)-18)-12=0



We calculate terms in parentheses: -(3(p-2)-18), so:

3(p-2)-18

We multiply parentheses

3p-6-18

We add all the numbers together, and all the variables

3p-24

Back to the equation:

-(3p-24)



We add all the numbers together, and all the variables

5p-(3p-24)-12=0

We get rid of parentheses

5p-3p+24-12=0

We add all the numbers together, and all the variables

2p+12=0

We move all terms containing p to the left, all other terms to the right

2p=-12

p=-12/2

p=-6

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