-7r-2(7+r)=2(8-3r)-6r

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Solution for -7r-2(7+r)=2(8-3r)-6r equation: 



-7r-2(7+r)=2(8-3r)-6r

We move all terms to the left:

-7r-2(7+r)-(2(8-3r)-6r)=0

We add all the numbers together, and all the variables

-7r-2(r+7)-(2(-3r+8)-6r)=0

We multiply parentheses

-7r-2r-(2(-3r+8)-6r)-14=0



We calculate terms in parentheses: -(2(-3r+8)-6r), so:

2(-3r+8)-6r

We add all the numbers together, and all the variables

-6r+2(-3r+8)

We multiply parentheses

-6r-6r+16

We add all the numbers together, and all the variables

-12r+16

Back to the equation:

-(-12r+16)



We add all the numbers together, and all the variables

-9r-(-12r+16)-14=0

We get rid of parentheses

-9r+12r-16-14=0

We add all the numbers together, and all the variables

3r-30=0

We move all terms containing r to the left, all other terms to the right

3r=30

r=30/3

r=10

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