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-7x(2x-8)=-16-6x
We move all terms to the left:
-7x(2x-8)-(-16-6x)=0
We add all the numbers together, and all the variables
-7x(2x-8)-(-6x-16)=0
We multiply parentheses
-14x^2+56x-(-6x-16)=0
We get rid of parentheses
-14x^2+56x+6x+16=0
We add all the numbers together, and all the variables
-14x^2+62x+16=0
a = -14; b = 62; c = +16;
Δ = b2-4ac
Δ = 622-4·(-14)·16
Δ = 4740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4740}=\sqrt{4*1185}=\sqrt{4}*\sqrt{1185}=2\sqrt{1185}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{1185}}{2*-14}=\frac{-62-2\sqrt{1185}}{-28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{1185}}{2*-14}=\frac{-62+2\sqrt{1185}}{-28} $
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