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-7x(3x-0.7)=0
We multiply parentheses
-21x^2+4.9x=0
a = -21; b = 4.9; c = 0;
Δ = b2-4ac
Δ = 4.92-4·(-21)·0
Δ = 24.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.9)-\sqrt{24.01}}{2*-21}=\frac{-4.9-\sqrt{24.01}}{-42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.9)+\sqrt{24.01}}{2*-21}=\frac{-4.9+\sqrt{24.01}}{-42} $
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