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-7x(3x-2)=-147
We move all terms to the left:
-7x(3x-2)-(-147)=0
We add all the numbers together, and all the variables
-7x(3x-2)+147=0
We multiply parentheses
-21x^2+14x+147=0
a = -21; b = 14; c = +147;
Δ = b2-4ac
Δ = 142-4·(-21)·147
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-112}{2*-21}=\frac{-126}{-42} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+112}{2*-21}=\frac{98}{-42} =-2+1/3 $
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