-7x+3(4x-5)=-40

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Solution for -7x+3(4x-5)=-40 equation: 



-7x+3(4x-5)=-40

We move all terms to the left:

-7x+3(4x-5)-(-40)=0

We add all the numbers together, and all the variables

-7x+3(4x-5)+40=0

We multiply parentheses

-7x+12x-15+40=0

We add all the numbers together, and all the variables

5x+25=0

We move all terms containing x to the left, all other terms to the right

5x=-25

x=-25/5

x=-5

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