-7x+8(2x-4)=40

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Solution for -7x+8(2x-4)=40 equation: 



-7x+8(2x-4)=40

We move all terms to the left:

-7x+8(2x-4)-(40)=0

We multiply parentheses

-7x+16x-32-40=0

We add all the numbers together, and all the variables

9x-72=0

We move all terms containing x to the left, all other terms to the right

9x=72

x=72/9

x=8

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