-7x-2(4x-3)=8(x+9)-30

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Solution for -7x-2(4x-3)=8(x+9)-30 equation: 



-7x-2(4x-3)=8(x+9)-30

We move all terms to the left:

-7x-2(4x-3)-(8(x+9)-30)=0

We multiply parentheses

-7x-8x-(8(x+9)-30)+6=0



We calculate terms in parentheses: -(8(x+9)-30), so:

8(x+9)-30

We multiply parentheses

8x+72-30

We add all the numbers together, and all the variables

8x+42

Back to the equation:

-(8x+42)



We add all the numbers together, and all the variables

-15x-(8x+42)+6=0

We get rid of parentheses

-15x-8x-42+6=0

We add all the numbers together, and all the variables

-23x-36=0

We move all terms containing x to the left, all other terms to the right

-23x=36

x=36/-23

x=-1+13/23

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