-7x-4(4-4x)=6(x-3)-4

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Solution for -7x-4(4-4x)=6(x-3)-4 equation: 



-7x-4(4-4x)=6(x-3)-4

We move all terms to the left:

-7x-4(4-4x)-(6(x-3)-4)=0

We add all the numbers together, and all the variables

-7x-4(-4x+4)-(6(x-3)-4)=0

We multiply parentheses

-7x+16x-(6(x-3)-4)-16=0



We calculate terms in parentheses: -(6(x-3)-4), so:

6(x-3)-4

We multiply parentheses

6x-18-4

We add all the numbers together, and all the variables

6x-22

Back to the equation:

-(6x-22)



We add all the numbers together, and all the variables

9x-(6x-22)-16=0

We get rid of parentheses

9x-6x+22-16=0

We add all the numbers together, and all the variables

3x+6=0

We move all terms containing x to the left, all other terms to the right

3x=-6

x=-6/3

x=-2

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