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-7x^2+11x+6=0
a = -7; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·(-7)·6
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-17}{2*-7}=\frac{-28}{-14} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+17}{2*-7}=\frac{6}{-14} =-3/7 $
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