-7x2+14x+21=0

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Solution for -7x2+14x+21=0 equation:



-7x^2+14x+21=0
a = -7; b = 14; c = +21;
Δ = b2-4ac
Δ = 142-4·(-7)·21
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-28}{2*-7}=\frac{-42}{-14} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+28}{2*-7}=\frac{14}{-14} =-1 $

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