-7x2+49=0

Solution for -7x2+49=0 equation:

-7x^2+49=0

a = -7; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-7)·49
Δ = 1372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1372}=\sqrt{196*7}=\sqrt{196}*\sqrt{7}=14\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{7}}{2*-7}=\frac{0-14\sqrt{7}}{-14}
=-\frac{14\sqrt{7}}{-14}
=-\frac{\sqrt{7}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{7}}{2*-7}=\frac{0+14\sqrt{7}}{-14}
=\frac{14\sqrt{7}}{-14}
=\frac{\sqrt{7}}{-1}
$