-7x2+6x+10=0

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Solution for -7x2+6x+10=0 equation:



-7x^2+6x+10=0
a = -7; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·(-7)·10
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{79}}{2*-7}=\frac{-6-2\sqrt{79}}{-14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{79}}{2*-7}=\frac{-6+2\sqrt{79}}{-14} $

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