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-7x^2-23x+10=0
a = -7; b = -23; c = +10;
Δ = b2-4ac
Δ = -232-4·(-7)·10
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{809}}{2*-7}=\frac{23-\sqrt{809}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{809}}{2*-7}=\frac{23+\sqrt{809}}{-14} $
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