-7x2-8x+9=0

Solution for -7x2-8x+9=0 equation:

-7x^2-8x+9=0

a = -7; b = -8; c = +9;
Δ = b2-4ac
Δ = -82-4·(-7)·9
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{79}}{2*-7}=\frac{8-2\sqrt{79}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{79}}{2*-7}=\frac{8+2\sqrt{79}}{-14}
$