-7y(1-y)+4y+3=7y2-3y+3

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Solution for -7y(1-y)+4y+3=7y2-3y+3 equation: 



-7y(1-y)+4y+3=7y^2-3y+3

We move all terms to the left:

-7y(1-y)+4y+3-(7y^2-3y+3)=0

We add all the numbers together, and all the variables

-7y(-1y+1)+4y-(7y^2-3y+3)+3=0

We add all the numbers together, and all the variables

4y-7y(-1y+1)-(7y^2-3y+3)+3=0

We multiply parentheses

7y^2+4y-7y-(7y^2-3y+3)+3=0

We get rid of parentheses

7y^2-7y^2+4y-7y+3y-3+3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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