-7y+3(y-2)=10

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Solution for -7y+3(y-2)=10 equation: 



-7y+3(y-2)=10

We move all terms to the left:

-7y+3(y-2)-(10)=0

We multiply parentheses

-7y+3y-6-10=0

We add all the numbers together, and all the variables

-4y-16=0

We move all terms containing y to the left, all other terms to the right

-4y=16

y=16/-4

y=-4

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