-7y+3(y-3)=19

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Solution for -7y+3(y-3)=19 equation:



-7y+3(y-3)=19
We move all terms to the left:
-7y+3(y-3)-(19)=0
We multiply parentheses
-7y+3y-9-19=0
We add all the numbers together, and all the variables
-4y-28=0
We move all terms containing y to the left, all other terms to the right
-4y=28
y=28/-4
y=-7

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