-7y+3(y-4)=-28

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Solution for -7y+3(y-4)=-28 equation: 



-7y+3(y-4)=-28

We move all terms to the left:

-7y+3(y-4)-(-28)=0

We add all the numbers together, and all the variables

-7y+3(y-4)+28=0

We multiply parentheses

-7y+3y-12+28=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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