-8(-3b+3)=40+8b

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Solution for -8(-3b+3)=40+8b equation: 



-8(-3b+3)=40+8b

We move all terms to the left:

-8(-3b+3)-(40+8b)=0

We add all the numbers together, and all the variables

-8(-3b+3)-(8b+40)=0

We multiply parentheses

24b-(8b+40)-24=0

We get rid of parentheses

24b-8b-40-24=0

We add all the numbers together, and all the variables

16b-64=0

We move all terms containing b to the left, all other terms to the right

16b=64

b=64/16

b=4

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