-8(2n+1)+7n=2-5(2n-1)

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Solution for -8(2n+1)+7n=2-5(2n-1) equation: 



-8(2n+1)+7n=2-5(2n-1)

We move all terms to the left:

-8(2n+1)+7n-(2-5(2n-1))=0

We add all the numbers together, and all the variables

7n-8(2n+1)-(2-5(2n-1))=0

We multiply parentheses

7n-16n-(2-5(2n-1))-8=0



We calculate terms in parentheses: -(2-5(2n-1)), so:

2-5(2n-1)

determiningTheFunctionDomain
-5(2n-1)+2

We multiply parentheses

-10n+5+2

We add all the numbers together, and all the variables

-10n+7

Back to the equation:

-(-10n+7)



We add all the numbers together, and all the variables

-9n-(-10n+7)-8=0

We get rid of parentheses

-9n+10n-7-8=0

We add all the numbers together, and all the variables

n-15=0

We move all terms containing n to the left, all other terms to the right

n=15

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