-8(2x+4)=-4x(4x+8)

Solution for -8(2x+4)=-4x(4x+8) equation:

-8(2x+4)=-4x(4x+8)

We move all terms to the left:

-8(2x+4)-(-4x(4x+8))=0

We multiply parentheses

-16x-(-4x(4x+8))-32=0


We calculate terms in parentheses: -(-4x(4x+8)), so:

-4x(4x+8)

We multiply parentheses

-16x^2-32x

Back to the equation:

-(-16x^2-32x)


We get rid of parentheses

16x^2+32x-16x-32=0

We add all the numbers together, and all the variables

16x^2+16x-32=0

a = 16; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·16·(-32)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-48}{2*16}=\frac{-64}{32}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+48}{2*16}=\frac{32}{32}
=1
$