-8(3b-7)=4-2(b+3)

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Solution for -8(3b-7)=4-2(b+3) equation: 



-8(3b-7)=4-2(b+3)

We move all terms to the left:

-8(3b-7)-(4-2(b+3))=0

We multiply parentheses

-24b-(4-2(b+3))+56=0



We calculate terms in parentheses: -(4-2(b+3)), so:

4-2(b+3)

determiningTheFunctionDomain
-2(b+3)+4

We multiply parentheses

-2b-6+4

We add all the numbers together, and all the variables

-2b-2

Back to the equation:

-(-2b-2)



We get rid of parentheses

-24b+2b+2+56=0

We add all the numbers together, and all the variables

-22b+58=0

We move all terms containing b to the left, all other terms to the right

-22b=-58

b=-58/-22

b=2+7/11

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