-8(4+2a)=-128

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Solution for -8(4+2a)=-128 equation: 



-8(4+2a)=-128

We move all terms to the left:

-8(4+2a)-(-128)=0

We add all the numbers together, and all the variables

-8(2a+4)-(-128)=0

We add all the numbers together, and all the variables

-8(2a+4)+128=0

We multiply parentheses

-16a-32+128=0

We add all the numbers together, and all the variables

-16a+96=0

We move all terms containing a to the left, all other terms to the right

-16a=-96

a=-96/-16

a=+6

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