-8(4b+2)=-11(b+11)

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Solution for -8(4b+2)=-11(b+11) equation: 



-8(4b+2)=-11(b+11)

We move all terms to the left:

-8(4b+2)-(-11(b+11))=0

We multiply parentheses

-32b-(-11(b+11))-16=0



We calculate terms in parentheses: -(-11(b+11)), so:

-11(b+11)

We multiply parentheses

-11b-121

Back to the equation:

-(-11b-121)



We get rid of parentheses

-32b+11b+121-16=0

We add all the numbers together, and all the variables

-21b+105=0

We move all terms containing b to the left, all other terms to the right

-21b=-105

b=-105/-21

b=+5

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