-8(6+2b)=-6(b-4)-2b

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Solution for -8(6+2b)=-6(b-4)-2b equation: 



-8(6+2b)=-6(b-4)-2b

We move all terms to the left:

-8(6+2b)-(-6(b-4)-2b)=0

We add all the numbers together, and all the variables

-8(2b+6)-(-6(b-4)-2b)=0

We multiply parentheses

-16b-(-6(b-4)-2b)-48=0



We calculate terms in parentheses: -(-6(b-4)-2b), so:

-6(b-4)-2b

We add all the numbers together, and all the variables

-2b-6(b-4)

We multiply parentheses

-2b-6b+24

We add all the numbers together, and all the variables

-8b+24

Back to the equation:

-(-8b+24)



We get rid of parentheses

-16b+8b-24-48=0

We add all the numbers together, and all the variables

-8b-72=0

We move all terms containing b to the left, all other terms to the right

-8b=72

b=72/-8

b=-9

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