-8(8-x)=2(2/5x+5)

Solution for -8(8-x)=2(2/5x+5) equation:

-8(8-x)=2(2/5x+5)

We move all terms to the left:

-8(8-x)-(2(2/5x+5))=0


Domain of the equation: 5x+5))!=0

x∈R


We add all the numbers together, and all the variables

-8(-1x+8)-(2(2/5x+5))=0

We multiply parentheses

8x-(2(2/5x+5))-64=0

We multiply all the terms by the denominator


8x*5x-64*5x+5))-(2(2+5))=0

We add all the numbers together, and all the variables

8x*5x-64*5x+5))-(27)=0

We add all the numbers together, and all the variables

8x*5x-64*5x=0

Wy multiply elements

40x^2-320x=0

a = 40; b = -320; c = 0;
Δ = b2-4ac
Δ = -3202-4·40·0
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{102400}=320$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-320}{2*40}=\frac{0}{80}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+320}{2*40}=\frac{640}{80}
=8
$